$2^{x-1}\cdot 2^{3-x}$ |
$4$ |
|
$125^x\cdot 5^x:25^{x-1}$ |
$5^{2x+2}$ |
|
$4^{x+2}\cdot 8^{x-1}$ |
$2^{5x+1}$ |
|
$25^{x-1}\cdot 5^{1-x}\cdot 5^{2x}$ |
$5^{3x-1}$ |
| a) $\displaystyle\left(3^{x-2}\right)^{x+2}:\left(3^{2x}\right)^{x-2}\cdot 3^{(x-2)^2}=$
1
|
||
b) $\displaystyle 16^{3x-2}\cdot4^{(x-1)^2}:\left(4^x\right)^{x+4}=$
|
||
| c) $\displaystyle 4^x\cdot 3^{2x}\cdot 2^{3x}=$
288
$^x$ |
| a) $\displaystyle 2^{x+2}-6\cdot2^x+7\cdot2^{x-2}$ |
| b) $\displaystyle 3^{x+3}-5\cdot3^{x+1}-9\cdot3^x$ |
| c) $\displaystyle 5\cdot4^{x+1}-7\cdot4^x+5^{x+1}+8\cdot5^x$ |
a) $a^{n+1}-3a^n-4a^{n-1}=$ $a$ n-1 $(a-$ 4 $)(a+$ 1 $)$
b) $x^{n}-4x^{n-2}=$ $x$ n-2 $(x-$ 2 $)(x+$ 2 $)$