a) $\sqrt[5]{(8\cdot{4})^4}-\sqrt{27:3}=\sqrt[5]{32^4}-\sqrt{9}=2^4-3=13$

b) $\sqrt{0,25}+\sqrt[3]{\frac{1}{8}}-4\cdot{\frac{1}{4}}=0,5+\frac{1}{2}-1=0$

c) $\sqrt{\sqrt[4]{16^3}+1}-3\sqrt{(\frac{25}{4})^{-1}}=\sqrt{9}-3\cdot{\frac{2}{5}}=3-\frac{6}{5}=1\frac{4}{5}$

č) $\sqrt{\sqrt{9^3}-2}+\sqrt[3]{\frac{27}{125}}\cdot{\sqrt{(\frac{4}{100})^{-1}}}=\sqrt{27-2}+\frac{3}{5}\cdot{\frac{10}{2}}=8$ 

a) $32^{\frac{4}{5}}-9^{\frac{1}{2}}=(2^5)^{\frac{4}{5}}-(3^2)^{\frac{1}{2}}=2^4-3=13$

b) $(0,5^2)^{\frac{1}{2}}+(2^3)^{-\frac{1}{3}}-4\cdot{\frac{1}{4}}=0,5+2^{-1}-1=0$

c) $((2^4)^{\frac{3}{4}}+1)^{\frac{1}{2}}-3\cdot{((\frac{25}{4})^{-1})^{\frac{1}{2}}}=$

$=(2^3+1)^{\frac{1}{2}}-3\cdot{(\frac{4}{25})^{\frac{1}{2}}}=1{\frac{4}{5}}$

č) $((3^2)^{\frac{3}{2}}-2)^{\frac{1}{2}}+((\frac{5}{3})^3)^{-\frac{1}{3}}\cdot{(0,2^2)^{-\frac{1}{2}}}=$

$=(3^3-2)^{\frac{1}{2}}+(\frac{5}{3})^{-1}\cdot{(\frac{1}{5})^{-1}}=(5^2)^{\frac{1}{2}}+3=8$

$\frac{(5^{\frac{1}{9}}\cdot{5^{\frac{2}{3}}}\cdot{5^{\frac{1}{3}}})^3}{(5^{\frac{2}{3}})^2}=\frac{(5^{\frac{1+6+3}{9}})^3}{5^{\frac{4}{3}}}=\frac{5^{\frac{10}{3}}}{5^{\frac{4}{3}}}=5^2=25$